Download PassLeader Free 70-761 Dumps with VCE and PDF (Question 46 – Question 50)

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QUESTION 46
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply only to that question.
You have a database that contains tables named Customer_CRMSystem and Customer_HRSystem. Both tables use the following structure:
passleader-70-761-dumps-461
The tables include the following records:
Customer_CRMSystem:
passleader-70-761-dumps-462
Customer_HRSystem:
passleader-70-761-dumps-463
Records that contain null values for CustomerCode can be uniquely identified by CustomerName. You need to display a list of customers that do not appear in the Customer_HRSystem table. Which Transact-SQL statement should you run?

passleader-70-761-dumps-464
passleader-70-761-dumps-465

A.    Option A
B.    Option B
C.    Option C
D.    Option D
E.    Option E
F.    Option F
G.    Option G
H.    Option H

Answer: D
Explanation:
EXCEPT returns distinct rows from the left input query that aren’t output by the right input query.
References: https://msdn.microsoft.com/en-us/library/ms188055.aspx

QUESTION 47
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply only to that question.
You have a database that contains tables named Customer_CRMSystem and Customer_ HRSystem. Both tables use the following structure:
passleader-70-761-dumps-471
The tables include the following records:
Customer_CRMSystem:
passleader-70-761-dumps-472
Customer_HRSystem:
passleader-70-761-dumps-473
Records that contain null values for CustomerCode can be uniquely identified by Customer Name. You need to display customers who appear in both tables and have a proper CustomerCode. Which Transact-SQL statement should you run?

passleader-70-761-dumps-474

A.    Option A
B.    Option B
C.    Option C
D.    Option D
E.    Option E

Answer: A
Explanation:
When there are null values in the columns of the tables being joined, the null values do not match each other. The presence of null values in a column from one of the tables being joined can be returned only by using an outer join (unless the WHERE clause excludes null values).
References: https://technet.microsoft.com/en-us/library/ms190409(v=sql.105).aspx

QUESTION 48
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply only to that question.
You have a database that contains tables named Customer_CRMSystem and Customer_ HRSystem. Both tables use the following structure:
passleader-70-761-dumps-481
The tables include the following records:
Customer_CRMSystem:
passleader-70-761-dumps-482
Customer_HRSystem:
passleader-70-761-dumps-483
Records that contain null values for CustomerCode can be uniquely identified by Customer Name. You need to display a Cartesian product, combining both tables. Which Transact-SQL statement should you run?

passleader-70-761-dumps-484
passleader-70-761-dumps-485

A.    Option A
B.    Option B
C.    Option C
D.    Option D
E.    Option E
F.    Option F
G.    Option G
H.    Option H

Answer: G
Explanation:
A cross join that does not have a WHERE clause produces the Cartesian product of the tables involved in the join. The size of a Cartesian product result set is the number of rows in the first table multiplied by the number of rows in the second table.
References: https://technet.microsoft.com/en-us/library/ms190690(v=sql.105).aspx

QUESTION 49
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply only to that question.
You have a database that contains tables named Customer_CRMSystem and Customer_HRSystem. Both tables use the following structure:
passleader-70-761-dumps-491
The tables include the following records:
Customer_CRMSystem:
passleader-70-761-dumps-492
Customer_HRSystem:
passleader-70-761-dumps-493
Records that contain null values for CustomerCode can be uniquely identified by Customer Name. You need to create a list of all unique customers that appear in either table. Which Transact-SQL statement should you run?

passleader-70-761-dumps-494
passleader-70-761-dumps-495

A.    Option A
B.    Option B
C.    Option C
D.    Option D
E.    Option E
F.    Option F
G.    Option G
H.    Option H

Answer: E
Explanation:
UNION combines the results of two or more queries into a single result set that includes all the rows that belong to all queries in the union. The UNION operation is different from using joins that combine columns from two tables.

QUESTION 50
Note: This question is part of a series of questions that use the same scenario. For your convenience, the scenario is repeated in each question. Each question presents a different goal and answer choices, but the text of the scenario is exactly the same in each question in this series.
Drag and Drop Question
You are developing a database to track customer orders. The database contains the following tables: Sales.Customers, Sales.Orders, and Sales.OrderLines. The following table describes the columns in Sales.Customers.
passleader-70-761-dumps-501
The following table describes the columns in Sales.Orders:
passleader-70-761-dumps-502
The following table describes the columns in Sales.OrderLines:
passleader-70-761-dumps-503
You need to create a function that accepts a CustomerID as a parameter and returns the following information:
– all customer information for the customer
– the total number of orders for the customer
– the total price of all orders for the customer
– the average quantity of items per order
How should you complete the function definition? To answer, drag the appropriate TransactSQL segment to the correct locations. Transact-SQL segment may be used once, more than once, or not at all. You may need to drag the split bar between panes or scroll to view content.
passleader-70-761-dumps-504

Answer:
passleader-70-761-dumps-505
Explanation:
Box1: RETURNS TABLE
The function should return the following information:
– all customer information for the customer
– the total number of orders for the customer
– the total price of all orders for the customer
– the average quantity of items per order
Box 2: COUNT
The function should return the total number of orders for the customer.
Box 3: SUM
The function should return the total price of all orders for the customer.
Box 3. AVG
The function should return the average quantity of items per order.
Box 4: GROUP BY
Need to use GROUP BY for the aggregate functions.
References: https://msdn.microsoft.com/en-us/library/ms186755.aspx


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